persamaan nilai mutlak ∣3x−2∣=∣5x∣
(3x - 2)² = (5x)²
(3x - 2)² - (5x)² = 0
(3x - 2 + 5x)(3x - 2 - 5x) = 0
(8x - 2)(-2x - 2) = 0
8x = 2
x = 2/8 = 1/4
-2x = 2
x = 2/-2 = -1
[tex]{ \green{ \boxed{ \boxed{ \sf{ {Answer \: by : AdhidMagelang}}}}}}[/tex]
Penjelasan dengan langkah-langkah:
[tex] |3x - 2| = |5x| [/tex]
PENENTUAN X1
[tex]3x - 2 = 5x[/tex]
[tex] - 2 = (5 - 3)x[/tex]
[tex]2x = - 2[/tex]
[tex]x1 = - \frac{ 2}{2} = - 1[/tex]
PENENTUAN X2
[tex]3x - 2 = - 5x[/tex]
[tex] - 2 = - (5 + 3)x[/tex]
[tex] - 8x = - 2[/tex]
[tex]x2 = \frac{ - 2}{ - 8} = \frac{1}{4} [/tex]
Maka, nilai x yang memenuhi yaitu
[tex]x1 = - 1 \: \: atau \: \: x2 = \frac{1}{4} [/tex]